Building up a square lattice - Revision history

Nice and Tidy at 09:59, 13 February 2008

2008-02-13T09:59:09Z

← Older revision		Revision as of 11:59, 13 February 2008
Line 25:		Line 25:
	* Coordinates:		* Coordinates:
	Atom 1: <math> \left( x_1, y_1\right) = \left( 0, 0 \right) </math>		Atom 1: <math> \left( x_1, y_1\right) = \left( 0, 0 \right) </math>
			[[category: computer simulation techniques]]

Noe at 13:16, 20 March 2007

2007-03-20T13:16:42Z

← Older revision		Revision as of 15:16, 20 March 2007
Line 1:		Line 1:
	* Consider:		* Consider:
	# a ~~cubic~~ simulation box whose sides are of length <math>\left. L \right. </math>		# a square simulation box whose sides are of length <math>\left. L \right. </math>
	# a number of lattice positions, <math> \left. M \right. </math> given by <math> \left. M = m^{3} \right. </math> ; with <math> m </math> being a positive integer		# a number of lattice positions, <math> \left. M \right. </math> given by <math> \left. M = m^{2} \right. </math> ; with <math> m </math> being a positive integer

	* The <math> \left. M \right. </math> positions are those given by:		* The <math> \left. M \right. </math> positions are those given by:
Line 8:		Line 8:
	x = i \times (\delta l) &; i=0,1,\cdots, m-1 \\		x = i \times (\delta l) &; i=0,1,\cdots, m-1 \\
	y = j \times (\delta l) &; j=0,1,\cdots, m-1 \\		y = j \times (\delta l) &; j=0,1,\cdots, m-1 \\
	~~z = k \times (\delta l) &; k=0,1,\cdots, m-1~~
	\end{array}		\end{array}

Line 21:		Line 20:
	</math>		</math>

	== Atomic position(s) on a ~~cubic~~ cell ==		== Atomic position(s) on a square cell ==

	* Number of atoms per cell: 1		* Number of atoms per cell: 1
	* Coordinates:		* Coordinates:
	Atom 1: <math> \left( x_1, y_1~~, z_1~~ \right) = \left( 0, 0, 0 \right) </math>		Atom 1: <math> \left( x_1, y_1\right) = \left( 0, 0 \right) </math>

Noe: New page: * Consider: # a cubic simulation box whose sides are of length $\left. L \right.$ # a number of lattice positions, $\left. M \right.$ given by $\left. M = m...$

2007-03-20T13:15:00Z

New page: * Consider: # a cubic simulation box whose sides are of length <math>\left. L \right. </math> # a number of lattice positions, <math> \left. M \right. </math> given by <math> \left. M = m...

New page

* Consider:
# a cubic simulation box whose sides are of length <math>\left. L \right. </math>
# a number of lattice positions, <math> \left. M \right. </math> given by <math> \left. M = m^{3} \right. </math> ; with <math> m </math> being a positive integer

* The <math> \left. M \right. </math> positions are those given by:
:<math>
\left\{ \begin{array}{ll}
x = i \times (\delta l) &; i=0,1,\cdots, m-1 \\
y = j \times (\delta l) &; j=0,1,\cdots, m-1 \\
z = k \times (\delta l) &; k=0,1,\cdots, m-1
\end{array}

\right.
</math>

where
<math>
\left.
\delta l = L/m
\right.
</math>

== Atomic position(s) on a cubic cell ==

* Number of atoms per cell: 1
* Coordinates:
Atom 1: <math> \left( x_1, y_1, z_1 \right) = \left( 0, 0, 0 \right) </math>

Building up a square lattice - Revision history

Nice and Tidy at 09:59, 13 February 2008

Noe at 13:16, 20 March 2007

Noe: New page: * Consider: # a cubic simulation box whose sides are of length \left. L \right. # a number of lattice positions, \left. M \right. given by \left. M = m...

Noe: New page: * Consider: # a cubic simulation box whose sides are of length $\left. L \right.$ # a number of lattice positions, $\left. M \right.$ given by $\left. M = m...$