Speed of sound - Revision history

Carl McBride: Added subscript

2012-05-23T13:59:03Z

Added subscript

← Older revision		Revision as of 15:59, 23 May 2012
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	:<math>c = \sqrt{ \left. \frac{\partial p}{\partial \rho} \right\vert_S } = \sqrt{ \frac{B_S}{\rho} }</math>		:<math>c = \sqrt{ \left. \frac{\partial p}{\partial \rho} \right\vert_S } = \sqrt{ \frac{B_S}{\rho} }</math>

	where <math>B</math> is the adiabatic [[Compressibility \|bulk modulus]], given by		where <math>B_S</math> is the adiabatic [[Compressibility \|bulk modulus]], given by

	:<math>B_S = \frac{C_p}{C_V} B_T</math>		:<math>B_S = \frac{C_p}{C_V} B_T</math>

2012-05-23T13:37:45Z

← Older revision		Revision as of 15:37, 23 May 2012
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	:<math>c = \sqrt{ \frac{C_p B_T}{C_V \rho} }</math>		:<math>c = \sqrt{ \frac{C_p B_T}{C_V \rho} }</math>

	=See also==		==See also==
	*[Cole equation of state]]		*[[Cole equation of state]]

	==References==		==References==

2012-05-23T13:37:05Z

← Older revision		Revision as of 15:37, 23 May 2012
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	:<math>c = \sqrt{ \frac{C_p B_T}{C_V \rho} }</math>		:<math>c = \sqrt{ \frac{C_p B_T}{C_V \rho} }</math>

			=See also==
			*[Cole equation of state]]

	==References==		==References==

2012-05-23T13:30:36Z

← Older revision		Revision as of 15:30, 23 May 2012
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	The '''speed of sound''' (<math>c</math>)		The '''speed of sound''' (<math>c</math>) can be written as:

			:<math>c = \sqrt{ \left. \frac{\partial p}{\partial \rho} \right\vert_S } = \sqrt{ \frac{B_S}{\rho} }</math>

	:<math>c := \sqrt{ ~~\left.~~ \frac{~~\partial p~~}{~~\partial~~ \rho} ~~\right\vert_S~~ } </math>		where <math>B</math> is the adiabatic [[Compressibility \|bulk modulus]], given by

			:<math>B_S = \frac{C_p}{C_V} B_T</math>

			where <math>C</math> is the [[heat capacity]] and <math>B_T</math> is the isothermal bulk modulus, leading to

			:<math>c = \sqrt{ \frac{C_p B_T}{C_V \rho} }</math>

			==References==
			<references/>

			[[category: classical mechanics]]

2012-05-23T12:40:29Z

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The '''speed of sound''' (<math>c</math>)

:<math>c := \sqrt{ \left. \frac{\partial p}{\partial \rho} \right\vert_S } </math>